Log[5](2x+1)-log[5]x=2

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Solution for Log[5](2x+1)-log[5]x=2 equation: 


Simplifying
Log[5](2x + 1) + -1log[5] * x = 2

Reorder the terms:
goL * 5(1 + 2x) + -1log[5] * x = 2

Reorder the terms for easier multiplication:
5goL(1 + 2x) + -1log[5] * x = 2
(1 * 5goL + 2x * 5goL) + -1log[5] * x = 2
(5goL + 10goxL) + -1log[5] * x = 2

Reorder the terms for easier multiplication:
5goL + 10goxL + -1 * 5glo * x = 2

Multiply -1 * 5
5goL + 10goxL + -5glo * x = 2

Multiply glo * x
5goL + 10goxL + -5glox = 2

Reorder the terms:
-5glox + 5goL + 10goxL = 2

Solving
-5glox + 5goL + 10goxL = 2

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-2 + -5glox + 5goL + 10goxL = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -5glox + 5goL + 10goxL = 0

The solution to this equation could not be determined.

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